This rectangular prism is intersected by a plane that contains points B, D, H, and F.
What is the perimeter of the cross section?
Round to the nearest tenth.
perimeter = BD + DH + HF + FB
BD = HF and DH = FB
so...
perimeter = HF + FB + HF + FB
perimeter = 2HF + 2FB
72 + 82 = HF2 → HF = \(\sqrt{113}\) cm
FB = 6 cm
perimeter = 2\(\sqrt{113}\) + 2(6)
perimeter = 2\(\sqrt{113}\) + 12
perimeter ≈ 33.3 cm
