+0

# total distance

+3
385
10
+1828

the total distance here is 275 or 150 !!

xvxvxv  Sep 26, 2014

#1
+91446
+13

Total distance is 0.5*5*30+|0.5*-20*15| = 75+150 = 225m

Total displacement = 0.5*5*30+(0.5*-20*15) = 75-150 = -75m

Melody  Sep 26, 2014
Sort:

#1
+91446
+13

Total distance is 0.5*5*30+|0.5*-20*15| = 75+150 = 225m

Total displacement = 0.5*5*30+(0.5*-20*15) = 75-150 = -75m

Melody  Sep 26, 2014
#2
+1828
+3

yes your answer is correct but I don't understand why you take 15 !! why not 20

in this step !

0.5*5*30+|0.5*-20*15|

xvxvxv  Sep 26, 2014
#3
+91446
+8

I don't understand.  I didn't take 15.  It was -20 m/s

Melody  Sep 26, 2014
#4
+1828
+8

yes yes ... now its very clear .. thank you melody ...

xvxvxv  Sep 26, 2014
#5
+91446
+8

You are very welcome

Melody  Sep 26, 2014
#6
+91446
+10

I am going to add this as an interest question so I thought I would comment a little further.

The vertical axis is m/s   the horizontal axis is seconds.

When you multiply these together the seconds cancel out and you are left with metres which is distance.

When you find the area of a rectangle it might be metres * metres so the units will be m^2

When you find the area under these lines the units are  m/s and seconds so the resultant unit is metres.

That is why you can find the distance travelled by finding the area under the curve.

If you have any comments or questions please post here. This is a really interesting and important concept.

Melody  Sep 26, 2014
#7
+80983
+5

Thanks for that explanation, Melody...I don't "do" Physics but I see what you are talking about.....!!!!

CPhill  Sep 27, 2014
#8
+91446
0

Thanks Chris.

Melody  Sep 27, 2014
#9
+91446
+10

Actually, now that i look at the actual graph it is really weird.

How can you go from +30m/s to -20m/s  in an instant.  Maybe it is in a different universe?

what I said before still goes though.

Melody  Sep 27, 2014
#10
+91446
0

"This distance/displacement question does looks interesting.

I understand the steps to solve and the other numbers, but where do you get 0.5 from?"

--------------------------

What I needed to find was the area between the curve (line) and the time (horizontal) axis.

The shape of this area is a triangle so I used the formula for the area of a triangle, THAT is where the 0.5 came from.

--------------------------

Maybe you could do a one off Ninja and pop this into the great answers to learn thread and pop it in under Physics?   If you don't it doesn't matter.

Melody  Sep 28, 2014

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