A kite is flying at an angle of elevation of about 40 degrees. All 80 meters of string have been let out. Ignoring the sag inn the string, find the height of the kite to the nearest meter. Someone help me figure this out please.

itsuikeike
Mar 10, 2017

#1**0 **

The kite string, the ground, and the height make a right triangle. The kite string is the hypotenuse, 80 meters. The angle between the ground and kite string is 40º.

sin40º = height/80

height = 80sin40º

height ≈ 51.423 meters

Guest Mar 10, 2017

#2**0 **

We can use the sine to solve this.....

The string length is the hypotenuse and we are looking for the oppsite side.....so we have

sin (40) = h / 80 where h is the height.....multiply both sides by 80

80 * sin (40) = h ≈ 51.42 ft

CPhill
Mar 10, 2017

#3**0 **

The kite string is the hypotenuse of a right triangle with the OPPOSITE leg being the height of the kite.

Sin40 = opp/hyp = height/80m

80 x sin 40 = height = 51.m (rounded)

ElectricPavlov
Mar 10, 2017