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I have the problem (4x-4)^2 = (2x+9)^2 + (2x)^2. I ended up with 4x^2-34-1 = 0. Is that right? and if so, how do I factor it correctly? thank you.
 Jan 31, 2012

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 #1
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(4x-4)^2 = (2x+9)^2 + (2x)^2
16x 2 - 32x + 16 = 4x 2 + 36x +81 +4x 2
8x 2 - 68x - 65 = 0

Then you have to use the quadratic formula to get the 2 irrational roots.
 Oct 9, 2013

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