Log4(x+2)+log4(x-2=2
I assume you want to find x
\(\log_4(x+2)+\log_4(x-2)= 2\\ \log_4((x+2)(x-2))=2 \\ (x+2)(x-2)=4^2\\x^2-4=16 \\ x^2= 20 \\ x=\pm2\sqrt5\)
However, the negative value is not valid in the original equation, so \(x = 2\sqrt5\)
