+0

# Triv

0
146
1

Log4(x+2)+log4(x-2=2

Guest Jun 15, 2017
Sort:

#1
+26402
+1

I assume you want to find x

$$\log_4(x+2)+\log_4(x-2)= 2\\ \log_4((x+2)(x-2))=2 \\ (x+2)(x-2)=4^2\\x^2-4=16 \\ x^2= 20 \\ x=\pm2\sqrt5$$

However, the negative value is not valid in the original equation, so $$x = 2\sqrt5$$

Alan  Jun 15, 2017

### 5 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details