Use the change of base formula to approximate the solution to log0.515 = 1 – 2x. Round to the nearest hundredth.
I'm not sure that the change of base formula would do much good here, since we're already using base 10....here's my approach...
log0.515 = 1 – 2x and we can write
log0.515 = log 10 - 2x rearrange
2x = log 10 - log0.515
2x = log (10/0.515) divide both sides by 2
x = log(10/0.515)/ 2 ≈ 1.288 ≈ 1.29 to the nearest hundredth
I'm not sure that the change of base formula would do much good here, since we're already using base 10....here's my approach...
log0.515 = 1 – 2x and we can write
log0.515 = log 10 - 2x rearrange
2x = log 10 - log0.515
2x = log (10/0.515) divide both sides by 2
x = log(10/0.515)/ 2 ≈ 1.288 ≈ 1.29 to the nearest hundredth