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# Very simple question buggin me out pls answer this is legit :)

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2n^2 divided by 2n ?

equals to 2? or 2n?

Virax1o1  Jun 1, 2017

#1
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$$\frac{2n^2}{2n} \\~\\ =\frac{2\,\cdot \, n\,\cdot \, n}{2\,\cdot\, n}$$

The   2's   in the numerator and denominator cancel.

$$=\frac{\not2\,\cdot \, n\,\cdot \, n}{\not2\,\cdot\, n} \\~\\ =\frac{n\,\cdot \, n}{n}$$

The   n's   in the numerator and denominator cancel.

$$=\frac{n\,\cdot\, \not{n}}{\not{n}} \\~\\ =n$$

(Also, when we canceled the n from the denominator we should say n ≠ 0 )

hectictar  Jun 1, 2017
edited by hectictar  Jun 1, 2017
Sort:

#1
+4728
+3

$$\frac{2n^2}{2n} \\~\\ =\frac{2\,\cdot \, n\,\cdot \, n}{2\,\cdot\, n}$$

The   2's   in the numerator and denominator cancel.

$$=\frac{\not2\,\cdot \, n\,\cdot \, n}{\not2\,\cdot\, n} \\~\\ =\frac{n\,\cdot \, n}{n}$$

The   n's   in the numerator and denominator cancel.

$$=\frac{n\,\cdot\, \not{n}}{\not{n}} \\~\\ =n$$

(Also, when we canceled the n from the denominator we should say n ≠ 0 )

hectictar  Jun 1, 2017
edited by hectictar  Jun 1, 2017
#2
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i mean dividing 2n^2 to 2n. Lol

not in somewhat fraction form.

ok, for example dividing 10 to 5 = 2

i meant literally simple way..

sorry for that because i can't even explain this one :P

Virax1o1  Jun 1, 2017
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Guest.....you are just dividing  "horizontally"......in essence, hectictar is doing the very same thing in a "fraction" form

10        and      10 / 2         are exactly the same thing....

2

CPhill  Jun 1, 2017
#4
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for some reason im answering a rational equation right now

in rational equation, you have to find the LCD right? for example the LCD was = 2n^2

the equation was :

n-6/2n

so the first thing to do is to divide the LCD to denominator

so it will end up like : 2n^2 divide  2n

Now my problem is how do i divide 2n^2 to 2n?

the possible anser be like : 2n or 2?

now it would look like : 2n(n-6) or 2(n-6)

I hope it is now clearer than before :D

btw tnx for you guys hardwork :)

Virax1o1  Jun 1, 2017
#5
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Why don't you post the problem????......we'll take a look at it.....

CPhill  Jun 1, 2017
#6
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n - 6/2n

Is this the problem?

If it is..it that exactly how it is written? Or is it

n - 6/(2n)

hectictar  Jun 1, 2017
#7
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it was exactly written like: (n-6)/(2n), LCD=2n^2

then im about to divide the LCD (which is 2n^2) to Denominator (which is 2n)

im wondering what would be the answer after i divide them both??

is it 2n or 2 ???

i was doing rational equation btw

Virax1o1  Jun 1, 2017
#8
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If this is exactly as the question is written...

(n - 6) / (2n)

This is also

=   n / (2n)   -   6 / (2n)

We can reduce the first fraction by n .

=   1 / 2        -   6 / (2n)

We can reduce the second fraction by 2.

=   1 / 2        -   3 / n

..........

I don't really know what you mean by " divide the LCD " .  Why do you want to divide the LCD ?

Is that what the instructions tell you to do?

Maybe the problem is

n - 6 / (2n)           ?

Reduce the second fraction by 2.

=   n - 3/n

We can get the LCD by multiplying the first term by n/n ,

which gives us

=   n2 / n   -   3 / n

=   (n2 - 3) / n

....

BTW, I see you became a member! Welcome aboard!

hectictar  Jun 1, 2017
edited by hectictar  Jun 1, 2017
#9
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Sorry for late reply i'm just having a mini break lately xD

i think you're right and yeah my intructor told me to do that..

Does in prime factorization also have "dividing LCD thing?" just our topic lately.

maybe i mistaken it for rational equation?

i'm actually having a summer tutorial in math tho

now with some bunch of paperworks..

Btw. thanks for help! it helped a TON!!

Virax1o1  Jun 1, 2017
#10
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Sometimes taking a little break definitely helps!

Hmmm, I don't really know if prime factorization has to do with the LCD ...