A tube of tennis balls is a cylinder with a radius of 3.8cm. It contains 3 balls which fit exactly inside it. What is the Volume of the empty space in the tube?
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The height of the cylinder = 6 times the radius of one tennis ball = 6 * 3.8 cm = 22.8 cm
The volume of the cylinder = pi * radius^2 * height =
pi * (3.8)^2 * 22.8 cm^3 (1)
The volume of the tennis balls [3 spheres ] is
3 ( 4/3) * pi * (3.8)^3 cm^3 = 4 pi (3.8)^3 cm^3 (2)
The empty space is (1) - (2) =
pi * (3.8)^2 * 22.8 - 4 pi (3.8)^3 ≈ 344.77 cm^3
