+0  
 
+1
1129
2
avatar+251 

So I had the correct answer to this question, and now I'm redoing it 10 minutes later and can't seem to get it correct even after using the equation in the textbook :S

 

 

\(m= 180 kg \)

\(g=9.8m/s^2\)

\({\mu}_{0} = 0.17 \)

\(a = {0.0062m}^{-2}\)

\({x}_{2}=10\)

\({x}_{1}=0\)

 

The textbook gives the answer of 6kJ but it rounds

The answer I got originally was something like 5997 i think.... now I get 6644.4

 

thanks for your help.

 Apr 17, 2017
edited by vest4R  Apr 17, 2017
 #1
avatar+33615 
+2

I get the following:

 

 

Note that you need x2 in metres and that 6644 J = 6.644 kJ.

 Apr 17, 2017
 #2
avatar+251 
+1

thanks alan for reinforcing that. It's frustrating when the textbook rounds down so far, or maybe it's an error. Either way, thank you.

 Apr 17, 2017

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