What is the area of the rectangle shown on the coordinate plane?
Enter your answer in the box. Do not round at any steps.
units²
Let A = length of one side
A = sqrt [ (1 - 4)^2 + (5 - 3)^2 ] = sqrt [ (-3)^2 + 2^2 ] = sqrt [13]
Let B = length of perpendicular side
B = sqrt [ (4 - 0)^2 + ( 3 - -3)^2 ] = sqrt [ 4^2 + 6^2] = sqrt [ 52] = sqrt [ 4 * 13] =
2*sqrt [13]
So.....the area = A * B = sqrt [13] * 2 sqrt [13] = 2 * 13 = 26 units^2