What is the area of to the nearest tenth of a square centimeter? Use special right triangles to help find the height.

jbouyer
May 16, 2017

#1**+2 **

This is a 30º-60º-90º triangle where the length of the side across from the 30º angle = 5 cm.

So...the length of the side across from the 60º angle = 5√3 cm.

area of triangle = (1/2)(base)(height)

area of triangle = (1/2)(5)(5√3 ) cm^{2}

area of triangle = 12.5√3 cm^{2}

area of triangle ≈ 21.7 cm^{2}

hectictar
May 16, 2017

#1**+2 **

Best Answer

This is a 30º-60º-90º triangle where the length of the side across from the 30º angle = 5 cm.

So...the length of the side across from the 60º angle = 5√3 cm.

area of triangle = (1/2)(base)(height)

area of triangle = (1/2)(5)(5√3 ) cm^{2}

area of triangle = 12.5√3 cm^{2}

area of triangle ≈ 21.7 cm^{2}

hectictar
May 16, 2017