+0  
 
+1
2877
1
avatar+292 

What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation isy=−23x+5y=−23x+5 ?

Enter your answer in the box.

 Dec 11, 2017
 #1
avatar+128460 
+4

y = -23x  +  5

 

The slope of a perpendicular line to this is  (1/23)

 

So....the equation of this line passing through (8,1) is

 

y =  (1/23) (x - 8)  + 1

 

y = (1/23)x - 8/23 + 1

 

y = (1/23)x - 8/23 + 23/23

 

y = (1/23)x + 15/23

 

 

cool cool cool

 Dec 11, 2017

1 Online Users

avatar