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what is the exponent rule of (2a^-3b)(6b^5c^-7)/4c^-9

Guest Mar 23, 2017
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 #1
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I think it is 2... Not sure Though. Lol.. TTYL.. XOX

Guest Mar 23, 2017
 #2
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(2a^-3b)(6b^5c^-7) / ( 4c^-9)  =

 

[2 * 6 / 4 ]  *  [b * b^5]  *  [ 1 / a^3]  * [ c^9 / c^7]  =

 

[12 / 4]  *  [ b^6 ] *  [ 1 / a^3 ] *  [ c ^2 ]   =

 

[ 3 b^6 c^2 ] / a^3

 

 

 

cool cool cool

CPhill  Mar 23, 2017

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