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what is the length of the legs if the hypotenuse is 15 √6?

 Aug 5, 2015

Best Answer 

 #1
avatar+118587 
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Well if it is a isosceles right angled triangle then the legs would be the same.

$$\\x^2+x^2=(15\sqrt6)^2\\\\
2x^2=225*6\\\\
x^2=225*3\\\\
x=15\sqrt3$$

 Aug 5, 2015
 #1
avatar+118587 
+5
Best Answer

Well if it is a isosceles right angled triangle then the legs would be the same.

$$\\x^2+x^2=(15\sqrt6)^2\\\\
2x^2=225*6\\\\
x^2=225*3\\\\
x=15\sqrt3$$

Melody Aug 5, 2015

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