There are an infinite number of such numbers!
For example, a=3, b=4 and c=5 satisfy a2 + b2 = c2
But if you multiply a, b and c by the same number, say, n then you will find that the numbers a=3n, b=4n and c=5n also satisfy a2 + b2 = c2
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I know pretty much nothing on Pythagoras.
But i remember watching a video, is it that A= triangle numbers
b= even
c=prime
its probably wrong like i said i know nothing about it.
But i'm sure its for right and triangles?
Hi MathsGod1
Here is a video you should watch and absorb :)
https://www.khanacademy.org/math/geometry/right_triangles_topic/pyth_theor/v/pythagorean-theorem
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Oh I almost forgot. Numbers that work for the pythagorean Theorem are called pythagorean triads.
what is the numbers that satisfies the pythagoras theorem ?
https://commons.wikimedia.org/wiki/File:Pythagorean.svg#/media/File:Pythagorean.svg
A Pythagorean triple consists of three positive integers a, b, and c, such that a2 + b2 = c2. Such a triple is commonly written (a, b, c), and a well-known example is (3, 4, 5). If (a, b, c) is a Pythagorean triple, then so is (ka, kb, kc) for any positive integer k.
Generating a triple:
A fundamental formula for generating Pythagorean triples given an arbitrary pair of positive integers m and n with m > n. The formula states that the integers
$$a = m^2 - n^2 ,\ \, b = 2mn ,\ \, c = m^2 + n^2$$
or
$$a = k\cdot(m^2 - n^2) ,\ \, b = k\cdot(2mn) ,\ \, c = k\cdot(m^2 + n^2)$$
form a Pythagorean triple.
Example:
$$\\ \text{If } m=2 \text{ and } n = 1:\\
a= 2^2-1^2 =4 - 1 = 3 \\
b = 2\cdot 2 \cdot 1 = 4 \\
c = 2^2 + 1^2 = 4+1=5$$
Pythagorean triple (3, 4, 5), because $$\small{\text{$3^2+4^2=5^2$}}$$