#1**+1 **

I don't have a lot of experience at this, but I'll give it a go

Arrange the data in order from lowest to highest

0, 1, 1, 2, 2, 2, 2, 2, 3, 3, 4, 4, 5, 5, 6

find the median = 2

find the median of the data set below the median = 2 = first quartile value

find the median of the data set above the median = 4 = third quartile value

Find the inter-quartile range (IQR) = third quartile value - first quartile value = 4 - 2 = 2

To find any possible lower outliers we find all the values less than

first quartile value - 1.5 (IQR) = 2 - (1.5)(2) = 2 - 3 = -1

There are no values less than -1

To find any possible highest outliers, we find all values greater than

third quartile value + 1.5 (IQR) = 4 + (1.5)(2) = 4 + 3 = 7

Tthere are no values greater than 7

So.....no outliers exist

CPhill
May 24, 2017