What is the sum of the first 25 terms of the sequence 3, 17, 31, 45, ... ?
+118608 What is the sum of the first 25 terms of the sequence 3, 17, 31, 45, ..
d=14 a=3 n=25
Sn=n/2(2a+(n-1)d) = 25/2(6+24*14)
$${\frac{{\mathtt{25}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}\left({\mathtt{6}}{\mathtt{\,\small\textbf+\,}}{\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{14}}\right) = {\mathtt{4\,275}}$$
+118608 What is the sum of the first 25 terms of the sequence 3, 17, 31, 45, ..
d=14 a=3 n=25
Sn=n/2(2a+(n-1)d) = 25/2(6+24*14)
$${\frac{{\mathtt{25}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}\left({\mathtt{6}}{\mathtt{\,\small\textbf+\,}}{\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{14}}\right) = {\mathtt{4\,275}}$$
