what is the vertex of the quadratic function f(x)=6x^2+12x-18
We have the form
Ax^2 + Bx + C = 6x^2 + 12x + ( - 18 )
The x coordinate of the vertex = -B / [ 2A] = -12 / [ 2 (6) ] = -12 / 12 = -1
And the y coordinate = 6(-1)^2 + 12((-1) + (-18) = 6 - 12 - 18 = -24
So....the vertex is ( -1, 24 )