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# what is the vertex of the quadratic function f(x)=6x^2+12x-18

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what is the vertex of the quadratic function f(x)=6x^2+12x-18

Guest May 25, 2017

#1
+79823
+1

We have the form

Ax^2 + Bx + C  =  6x^2 + 12x + ( - 18 )

The x coordinate of the vertex  =   -B / [ 2A]  =   -12 / [ 2 (6) ]  =  -12 / 12   = -1

And the y coordinate  =   6(-1)^2 + 12((-1)  + (-18)    =   6 - 12  - 18   =   -24

So....the vertex  is   ( -1, 24 )

CPhill  May 25, 2017
Sort:

#1
+79823
+1

We have the form

Ax^2 + Bx + C  =  6x^2 + 12x + ( - 18 )

The x coordinate of the vertex  =   -B / [ 2A]  =   -12 / [ 2 (6) ]  =  -12 / 12   = -1

And the y coordinate  =   6(-1)^2 + 12((-1)  + (-18)    =   6 - 12  - 18   =   -24

So....the vertex  is   ( -1, 24 )

CPhill  May 25, 2017

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