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what is (y-5)/2<-x/3

EKC4000  Sep 24, 2017
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 #1
avatar+109 
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You have to make this more clear. Are we solving x in terms of y or vice versa? I am going to assume that it is in terms of y.

 

 

What is \(\frac{y-5}{2}<-\frac{x}{3}\) ?

 

Multiply 6 on both sides to get \(3y-15<-2x\)

 

Divide -2 on both sides, but we have to change the sign \(-\frac{3}{2}y+\frac{15}{2}>x\)

Jeff123  Sep 24, 2017
 #2
avatar+91229 
+1

Hi Jeff

You maths is fine but you have not made either x or y the subject.

Yours is fine, you only had to put x on the left hand side  wink

 

what is (y-5)/2<-x/3

 

Make x the subject:

\((y-5)/2<-x/3\\ \frac{3(y-5)}{2}<-x\\ \frac{-3(y-5)}{2}>x\\ x<\frac{-3(y-5)}{2}\\ or\\ x<\frac{3(5-y)}{2}\\\)

 

Make y the subject

 

\(\frac{y-5}{2}<\frac{-x}{3}\\ y-5<\frac{-2x}{3}\\ y<-\frac{2x}{3}+5\\ \)

Melody  Sep 24, 2017

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