what will be the value of cot(sin(inverse)(1/3))
let $$\theta=sin^{-1}(1/3)$$
$$cot\theta=\sqrt{8}=2\sqrt2$$
But $$sin\theta>0$$ so theta could be in the 1st otr second quadrant so
$$cot\theta=\pm2\sqrt2$$
$$cot(sin^{-1}(1/3))=\pm2\sqrt2$$