What would the chance of getting something that you have a 1/683 chance of getting in 683 tries?

If each try is independent from every other try and the probability of success is 1/683 and there are 683 tries, then the probability of failure is (682/683)⁶⁸³ because the probability of failure each time is 682/683 and you have to fail each of the 683 times.

So, the probability of success is 1 - (682/683)⁶⁸³ since the probability of success + the probability of failure is exactly 1 --- which means that the probability of success is 1 - probability of failure.

Thanks Geno,

I would not have thought of that. :)