Which statement explains why ABC is congruent to A′B′C′A′B′C′ ?

You can map △ABC onto △A′B′C′△A′B′C′ by reflecting it over the y-axis and translating it 4 units down, which is a sequence of rigid motions.

You can map △ABC onto △A′B′C′△A′B′C′ by reflecting it over line y = x and translating it 5 units right, which is a sequence of rigid motions.

You can map △ABC onto △A′B′C′△A′B′C′ by rotating it 90° clockwise about the origin and translating it 5 units right, which is a sequence of rigid motions.

You can map △ABC onto △A′B′C′△A′B′C′ by reflecting it over the x-axis and translating it 7 units right, which is a sequence of rigid motions.