which value of x is a solution to the equation 13-36x2=-12?
13 - 36x2 = -12 Subtract 13 from both sides of the equation.
-36x2 = -25 Divide both sides of the equation by -36 .
x2 = 25 / 36 Take the ± square root of both sides.
x = ± √[ 25 / 36 ]
x = ± 5/6