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d^2*d^6

Guest Feb 22, 2017
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 #1
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k^8/k^3 plz help

Guest Feb 22, 2017
 #2
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d^2*d^6

 

= d*d    *    d*d*d*d*d*d

 

there are 8 d's all multiplied together

 

\(=d^8\)

Melody  Feb 22, 2017
 #3
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k^8/k^3

 

\(\frac{k^8}{k^3}\\ =\frac{kkkkkkkk}{kkk}\\ =\frac{\not{k}\not{k}\not{k}^1kkkkk}{\not{k}\not{k}\not{k}^1}\\ =\frac{1*k^5}{1}\\ =k^5\)

Melody  Feb 22, 2017

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