d^2*d^6
k^8/k^3 plz help
= d*d * d*d*d*d*d*d
there are 8 d's all multiplied together
\(=d^8\)
k^8/k^3
\(\frac{k^8}{k^3}\\ =\frac{kkkkkkkk}{kkk}\\ =\frac{\not{k}\not{k}\not{k}^1kkkkk}{\not{k}\not{k}\not{k}^1}\\ =\frac{1*k^5}{1}\\ =k^5\)
