x^2+y^2+3x-2y-1=0 find the standard form

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Guest Oct 29, 2017

CPhill · Answer 1 · 2017-10-29T05:33:23

Rewrite as

x^2 + 3x + y^2 - 2y = 1

Complete the square on x and y

x^2 + 3x + 9/4 + y^2 - 2y + 1 = 1 + 9/4 + 1

( x + 3/2)^2 + ( y - 1)^2 = 2 + 9/4

( x + 3/2)^2 + ( y - 1)^2 = 8/4 + 9/4

( x + 3/2)^2 + ( y - 1)^2 = 17/4