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# z is directly proportional to the square of x and inversely proportional to the square root of y. If z=12 when x=2 and y=4, find z when x=6

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z is directly proportional to the square of x and inversely proportional to the square root of y. If z=12 when x=2 and y=4, find z when x=6 and y=32

any help is greatly appreciated!

Guest Jun 3, 2017
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We have  $$z=k\frac{x^2}{\sqrt{y}}$$   where k is a constant

Find k as  $$k=12\frac{\sqrt{4}}{2^2}\rightarrow6$$

So when x = 6 and y = 32 we have $$z=6\frac{6^2}{\sqrt{32}}\rightarrow27\sqrt2$$

.

Alan  Jun 3, 2017

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