So, I got something for the first section!

There are three possible categories of arrangements for \((a, b, c)\). They are:

- \((a, b, c)\) are equal.
- \((a, b, c)\) are all different.
- Two variables are equal, one is not.

There are \(6\binom{n}{3}\) arrangements when all the variables are different. \(\binom{n}{3}\) accounts for all the arrangements regardless of order, but we must multiply by 6 to get our final answer.

There are \(n\) arrangements when all the variables are the same.

There are \(3n(n - 1)\) ways to compute the arrangements when two variables are the same, and one is not equal.

Now, I need to figure out b; which I cannot.