you can use the second equation of motion s= ut+1/2at^2
here consider that the ball was at rest before kicking . and came to rest after comming to ground
and a=10m/s^2 (9.8) BECAUSE IT IS UNDER THE INFLUENCE OF GRAVITY.
this is only true if the ball is kicked vertically upward .
but if the ball was in a projectile motion i.e. in a 2D motion then apply the formula
H =v02sin2 θ/2g
H = maximum height (m)
v0 = initial velocity (m/s)
g = acceleration due to gravity (9.80 m/s2)
θ = angle of the initial velocity from the horizontal plane (radians or degrees).