The formula to find the axis of symmetry for any parabola is x= -b/(2a) for the quadratic equation of ax^2+bx+c.

(a) Therefore, the formula for the axis of symmetry for this parabola is x= 14/(-2) = -7. The final answer is x=-7.

(b) By top, I am assuming you mean the vertex. Since we know the axis of symmetry, x=-7, we know that the x-coordinate of the vertex of the parabola is -7. Substituting x=-7 into the quadratic equation, we get:

-49+98-53=-4

So, the coordinates for the vertex of the parabola is (-7,-4)

(c) The graph would look like: