HighSchoolDx

T = 4J/9

2J - 42 = T

Solving, J = 27 and T = 12

27 - 21 is 6. and 12 - 6 = 6. The answer is 6.

I found these articles that helped me understand your question. I hope they will help you, too.

https://mathcracker.com/quadratic-equation-formula

https://www.purplemath.com/modules/sqrvertx2.htm

Lets use the variables A and L. 

There is, A - 75 + L = 6(A - 75).

Also, A - 75 + L - 60 = 3(A - 75). 

solving the equations, I get A = 95, and L = 100.Therefore, the total is 195.

This is gcf or lcm problem...Dont know which one, but

There are less than 45 apples, but the number is divisible by both 3 and 5. This will mean it is divible by 15 too. if 45 is not an option, we will look at the next greatest multiple of 15 under that which is 30. 30 is the greatest possible number of apples.

yes. there is 3 and also -3 for y. that is all

So this is the problem:

A fruit stall owner had some apples and oranges. He sold an equal number of apples and oranges. He had 1/3 of the apples and 5/9 of the oranges left. What fraction of the fruits were sold?

2/3 of the apples is equal to 4/9 of the oranges. So...

2A/3 = 4O/9, and A is total apples and O is total oranges.

You want (2A/3 + 4O/9) / (A + O).

Look, that all of us can write O as 6A /4 or 3A/2.

So.... that means, the expression turns into (2A/3 + 4(3A/2)/9) / (A + 3A/2).

This simplifies to 8/15!!! Lol. The answer is 8/15. 

OMG 

Thank you both for answering my question with such detailed solutions... i upvoted yourposts! :)

Can confirm. also, the number is 685528825939742403772959575428195371930634×13 + 11, so the remainder is 11 :D :P

The sequence goes... 2, 1, 3, 4, 7, 11

So... the FIFTH value is 7.