Let's use the reverse process. Assume p is Mr.Perez's age and d is his daughter's age. Because there are two people's ages combined, we multiply 15 by 2, =30. 86-30 = 56.The ratio p:d is 3:1, 3+1 = 4, and 56/4 = 14. 14*3 gives us 42.
To check, 42/3 = 14, 42+14+15+15=56+30=86.
Mr.Perez is 42 now, and his daughter is14 now. If you have any questions, don't hesitate to ask. :)
Perhaps you could use the thumb as a variable(t)... You use the length between the two sides, probably at the base of the nail, and count. Remember, you need to keep track of your starting point and don't forget to go in a straight line! Assuming you count x 'thumbs', even if x is a decimal, we do tx and that's the approximate circumfrence. Good luck! This is an intriguing question...
So you have 2 courses, 70% of A for course one, and 80% for course 2, and 90% chance to pass at least one? That doesn't make sense... also, I'm not sure about what a passing grade is, and there is also insufficent information to determine the answer. At least that's what I think. Sorry I couldn't help you!
Alright, the answer is 3276. Without any restrictions, there a total of ways that the three people can be seated. We must then subtract the cases where at least two people are adjacent. There are two possible cases.
Case 1. All three people are sitting next to each other, in one block.
There are 18 ways to choose three consecutive seats. There are then 3! = 6ways to place the three people, which gives us 18 * 6 =108 possible seatings.
Case 2. There are two people sitting next to each other, and the third person is not next to either of them.
There are 18 ways to choose two consecutive seats. There are then 14 ways to choose the third seat. After the three seats have been chosen, there are ways to place the three people, which gives us 18*14*6=1512 possible seatings.
Therefore, there are 4892-108-1512 = 3276 seatings where no two people are adjacent.
Thank you all for the effort, it's greatly appreciated!