We see that the rectangle with side lengths 5 and 10 have an area of 50 and another rectangle with the same sides on the opposite side.

The two bottom rectangles have side lengths 3.6 and 10 have a combined area of 3.6*2*10 = 72.

The two front triangles have bases of 6 and heights 2 and 4 which have a combined area of \(\dfrac{6\cdot2}{2}\cdot \dfrac{6\cdot4}{2} = 6\cdot 12= 72\)

There are also the two triangles on the back which have the same area.

Thus the total surface area is 72+72+72=216.