Just a quick question, how did you form the equations QR = 2 (OQ * sin∠QOP) and h = sqrt[PQ2 - (QR/2)2] = 12*sqrt(3)?

Sorry, I was addressing jugoslav... his answer may be correct, but his answer is expressed as a decimal. Also jugoslav, how did you form the equation QR = 2 (OQ * sin∠QOP?

Can you express your answer as a sqrt please?

Hmm... your answer is wrong Pangolin14... not really sure what went wrong though...

Never mind... it took me many hours of frustration and wanting to punch myself for being dumb [I said 144/2 was 77 (T_T)], but I got every part! If you see this, no need to solve!

Also, make sure to be detailed in your explanation!