Well lets do some algebra!
\(a^3 + 3ab^2 = 679\)
\(a^3 - 3ab^2 = 673\)
\(a^3 + 3ab^2 = 679 \) this is equal to
\(a^3 - 3ab^2 = 679 - 6ab^2\)
we can conclude that
\(673 = 679 - 6ab^2\)
\(6 = 6ab^2\)
\(ab^2 = 1\)
Most likely a will be very big because we need a^3 to equal something large since the second term is = to 3.
so a^3 = 676 so a = \(\sqrt[3]{676}\)
b = \(\sqrt{\frac{1}{\sqrt[3]{676}}},-\sqrt{\frac{1}{\sqrt[3]{676}}}\)
a - b = \(\sqrt[3]{676}-\frac{1}{\sqrt{\sqrt[3]{676}}},\sqrt[3]{676}+\frac{1}{\sqrt{\sqrt[3]{676}}}\) that is so definenly incorrect, so plz someone see if this is correct or not
