Use pythagorean theorem to find the side of the smaller triangle.

\(1^2+b^2=5^2\)

\(b=2\sqrt6\)

So continuing with the pythagorean thereom \(2\sqrt{6}^2+5^2=c^2\)

\(c=\sqrt{37}\)

I am assuming the problem asks for a square root version.

Yes I now realize my mistake. If you look in the beginning of my answer you see that I used \(5\) instead of \(5^2\)

Here is my edited answer...

Use pythagorean theorem to find the side of the smaller triangle.

\(1^2=b^2=5^2\)

\(1+b^2=25\)

\(b^2=24\)

\(b=\sqrt{24}\)

So continuing with the pythagorean thereom \(\sqrt{24}^2+5^2=c^2\)

\(24+25=c^2\)

\(24+25=49\)

\(\sqrt{49}=7\)

Therefore the answer is \(7\)

Thanks, ElectricPalov and SoulSlayer615 for correcting my previous error,

\(\pi\)