+56 +56 #14+56 Ok so I'm not an expert with explanations but I'll try to explain myself.

Ok so if we count up 10 random multiples of 4 like 24,48,12,16,20,96,28,32,36,40. Note that every time 4, 8, or 0 is the last number, the preceding integer is even. When 2 or 6 is the last number the preceding integer is odd. So now say we have a number like 712. Because 2 is the last number, whatever comes before it has to be an odd number which in this case is 1 and it is odd, So 712 is evenly divisible by 4. Now if this number were 722, because 2 is even, it would have to be followed be either a 0, 4,or 8, to be divisible. So 728, 724, and 720 are all divisible by 4. With this in mind someone can give you any set of numbers. Such as 9848795 (random number) because this number ends with an odd number, all you would have to change the 5 to a 2 or 6 and you have a multiple of 4.

Ok so as you can see with the multiples of four, none end in 1,3,5,7, or 9 so any big number ending with one of those is not perfectly divisible by 4. Now if it ends in 0,2,4,6 or 8 then just perform the little test and you can see if its divisible by 4. Ok so, to sum it all up,

All multiples of 4 end in 0,2,4,6, or 8. If it ends in 2 or 6, check to see if the number preceding is odd or even. If it is odd then that number is divisible by 4. If the number ends in 0,4, or 8 then check to see if the preceding number is even. If it is even then the number is divisible by 4.

So with that information is 476,850,436 divisible by 4?

P.S. Thanks for the help with my atrocity of a problem Melody.