Thank you so much!!

Thank you!!

In part B, how did you split the bottom x-4 into (x+2)(x-2) I thought you could only do that if it was (x-4)^2?

Thank you so much! I believe on our test it'll be specified that we need to use the quotient method, just to check if we know it..but if it isn't I will use that trick! Thanks! I like the power rule better too.

Uh I meant a point on the graph. Answer is (2,-8).. I figured it out. but thank you, I do need to graph it later on.

Thank you!

Thank you! I'm not allowed to use a calculator to graph on the test and I don't really understand the graph aspect of this yet...but this is what I needed to show on the problem, so thanks! I will definitely be looking into the graphing though, as that is something I really struggle with.

Thank you! I understand now :)

The area of a square = (s^2). All sides are equal.

You need to work backwards since they give you area = 25m squared.

Square root the area to get rid of the square.

sqrt(25)= 5

The length of the edging = 5m

7/10 is bigger.

To reach this answer you take a common denominator by multiplying the given denominators with the opposite numerators.

7(14)= 98 9(10)=90

Thus 98 > 90.

6x-6+10x+6+28 = 16x + 28

(729/9)/54 = 81/54 = 3/2 [This is wrong, see CPhill's answer for correct answer.]