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1. what is the number of complex zeros for the polynomial function?

f(x)=x3−96x2+400

 

 

 

2. Divide.

(x3−8x2+2)÷(x−3)

 

 

A) x2−5x−15−43/x−3

B) x2−5x−15+43/x−3

C) x2−5x−15+47/x−3

D) x2−5x+15−43/x−3

Guest Nov 2, 2017
 #1
avatar+7339 
+1

This is the second one.

 

 

So the final result is     x2 - 5x - 15 - 43 / [ x - 3 ]

hectictar  Nov 2, 2017
 #2
avatar+92429 
+2

f(x)=x^3−96x^2+400

 

The number of complex zeroes is either 2 or 0

 

Look at the graph :   https://www.desmos.com/calculator/eodpv407b2

 

There are 3 real roots....so.....no roots are complex

 

 

cool cool cool

CPhill  Nov 2, 2017

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