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1. Enter the amplitude of the function f(x) .

f(x)=−2sin(3x)−1

 

2. What is the equation of the midline for the function f(x) ?

 

f(x)=3cos(x)−2.5

 

Enter your answer in the box.

 Jan 26, 2019
 #1
avatar+109519 
+1

Learn from the answers that i have already given you.

 Jan 26, 2019
 #2
avatar+109519 
+1

See if you ideas work by plotting you graph in here

 

https://www.desmos.com/calculator

 Jan 26, 2019
 #3
avatar+111328 
0

1. Enter the amplitude of the function f(x) .

f(x)=−2sin(3x)−1

 

In the form  Asin (Bx) + C

The amplitude =  l A l   =  l -2 l  = 2

 

 

 

2. What is the equation of the midline for the function f(x) ?

 

f(x)=3cos(x)−2.5

 

Note that the max for the function is 3(1) - 2.5   =  0.5

And the min for the function is    3(-1) - 2.5 =  -5.5

 

To find the midiine.....add these values and divide the sum by 2

So we have

[ . 5  + - 5.5] / 2 =     -5/2 =  -2.5

 

So....the equation for the midline is   y = -2.5

 

 

cool cool cool

 Jan 26, 2019

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