1. Enter the amplitude of the function f(x) .

f(x)=−2sin(3x)−1

2. What is the equation of the midline for the function f(x) ?

f(x)=3cos(x)−2.5

Enter your answer in the box.

Guest Jan 26, 2019

#3**0 **

1. Enter the amplitude of the function f(x) .

f(x)=−2sin(3x)−1

In the form Asin (Bx) + C

The amplitude = l A l = l -2 l = 2

2. What is the equation of the midline for the function f(x) ?

f(x)=3cos(x)−2.5

Note that the max for the function is 3(1) - 2.5 = 0.5

And the min for the function is 3(-1) - 2.5 = -5.5

To find the midiine.....add these values and divide the sum by 2

So we have

[ . 5 + - 5.5] / 2 = -5/2 = -2.5

So....the equation for the midline is y = -2.5

CPhill Jan 26, 2019