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I am kinda confused about this question, because I keep messing up, so I kinda need help:

Find all values of such that \(t-1\) , \(t+1\)and 4 could be the lengths of the sides of a right triangle.

Thanks!!!smiley

 Mar 4, 2021
 #1
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t+1 is obviously larger than t-1

 

assuming t+1 hypotenuse

 

(t+1)^2 = (t-1)^2  + 4^2

      expand and solve for t

 

Now   t+1   might be less than 4

then

4^2  = (t+1)^2   + (t-1)^2       expand and solve for more values of 't'

 

Remenber to check the values ot  t+1   and t-1   to make sure they 'fit' the assumptions

 Mar 4, 2021
edited by ElectricPavlov  Mar 4, 2021
 #2
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+1

Thanks! I got it now. I just checked over my work, and realized that I forgot to square the 4! Now, I got 4 and sqrt of 7! Thanks!

Guest Mar 4, 2021

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