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# Alg 2 help quiz plz!

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352
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#1

Use technology or a z-score table to answer the question.

The weights of boxes of rice produced at a factory are normally distributed with a mean of 24 ounces and a standard deviation of 1.3 ounces. Consider a shipment of 1200 boxes of rice.

How many of the boxes will weigh 25 ounces or less?

192

265

935

1008

#2:

Suppose the scores on a grammar quiz are normally distributed with a mean of 76 and a standard deviation of 8.

Which group describes 16% of the population of grammar quiz scores?

scores below 60

scores below 68

scores above 80

scores above 94

#3

The ages of people entering a pie eating contest are normally distributed with a mean of 35 years and a standard deviation of 8.2 years.

What is the age of a pie eating contestant with a z-score of −2.1 ?

#4

Use technology or a z-score table to answer the question.

The weights of books in a bookcase are normally distributed with a mean of 11.6 pounds and a standard deviation of 1.3 pounds. There are 136 books on the bookshelf.

How many of the books will weigh 10 pounds or more?

109

116

121

130

Apr 19, 2019

#1
+1

#1

Use technology or a z-score table to answer the question.

The weights of boxes of rice produced at a factory are normally distributed with a mean of 24 ounces and a standard deviation of 1.3 ounces. Consider a shipment of 1200 boxes of rice.

How many of the boxes will weigh 25 ounces or less?

[ 25 - 24 ] / 1.3  = .77 =  z score  translates to  0.7794

So...about 78% will weight 25 ounces or less ≈ 936   [ 935 is the closest answer ]   Apr 19, 2019
#2
+1

#2:

Suppose the scores on a grammar quiz are normally distributed with a mean of 76 and a standard deviation of 8.

Which group describes 16% of the population of grammar quiz scores?

This will be all the scores less than  1 standard deviation below the mean.......so....this will represent all the scores  <  76 - 8  =  68   Apr 19, 2019
#3
+1

#3

The ages of people entering a pie eating contest are normally distributed with a mean of 35 years and a standard deviation of 8.2 years.

What is the age of a pie eating contestant with a z-score of −2.1 ?

[ Age - 35 ] / [ 8.2]  =  -2.1     multiply both sides by 8.2

Age - 35   =  -17.22       add 35 to both sides

Age  ≈ 17.8  years   Apr 19, 2019
#4
0

I also forgot to add in this question:

Use technology or a z-score table to answer the question.

The expression  P(z<1.33) represents the area under the standard normal curve below the given value of z.

What is  P(z<1.33)?

0.0918

0.0934

0.9066

0.9082

Guest Apr 19, 2019
#5
+1

Use technology or a z-score table to answer the question.

The weights of books in a bookcase are normally distributed with a mean of 11.6 pounds and a standard deviation of 1.3 pounds. There are 136 books on the bookshelf.

How many of the books will weigh 10 pounds or more?

[ 10 - 11.6] / 1.3  = -1.23  z score which translates to  .1093

So  [ 1 - .1093] (136)  ≈   121  weigh 10 pounds or more   Apr 19, 2019