+0  
 
0
428
2
avatar+87 

Suppose the scores on a history quiz are normally distributed with a mean of 73 and a standard deviation of 4. Which group describes 16% of the population of history quiz scores ? 

Scores below 65

scores below 75

scores above 77 

scores above 81 

 Apr 9, 2019
 #1
avatar+6196 
+2

quick rule of thumb

 

16% of the population is a z-score of -1, i.e. 1 sigma less than the mean.

 

\(\dfrac{x - \mu}{\sigma} = -1 \Rightarrow x = \mu - \sigma\)

 

So we would have scores less than 73-4 = 69 being 16%

 

This doesn't match any of the choices so we note that it could be the top 16% in which case the z-score is 1 and we have

 

scores greater than x = 73+4 = 77 being 16%

 

this matches the 3rd choice.

 Apr 9, 2019
 #2
avatar+25918 
0

Look at your Negative z-score table .....look for a number close to 16% (.16)

I find   .99 z score is .1611

.99 x  standard deviation = .99 x 4 ~~ 4           73 - 4 = 69 

 

This question was submitted earlier ....it has an error in it somewhere

 

If we use  1.6%    look for number    .016 -ish      z -score -2.14

 

73  - 2.14 x 4 = 64.44     so I would go with the answer    'Scores below 65'     if it really is 1.6%    and not 16%

 

 

Or as Rom points out ....maybe it is the opposite end of the spectrum...the TOP 16% (and we were looking at it from the wrong perspective)

100% -16% = 84     look at positive z-score table for   .84 -ish  approx 1.0 standard deviations ABOVE the mean

      73 + 1 Standard deviation = 73+4 = 77 --------> choice #3   

    Thanx Rom!

 Apr 9, 2019
edited by ElectricPavlov  Apr 9, 2019

19 Online Users

avatar
avatar
avatar
avatar
avatar
avatar
avatar