In pentagon $MATHS$, \($\angle M \cong \angle T \cong \angle H$\) and $\(\angle A$ \)is supplementary to \($\angle S\)$. How many degrees are in the measure of $\angle H$?
In a pentagon, the sum of its interior angles measures 180 * 3 = 540 degrees.
Let angle M = angle T = angle H = y.
Thus, the remaining angles measures 540-3y
Let angle A = x and angle S = 180 - x
x + (180-x)=540-3y
Solving for y, we get 3y=360
y= 120 degrees. Angle H measures 120 degrees.