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A standard deck of 52 cards has 13 ranks (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King) and 4 suits \(($\spadesuit$, $\heartsuit$, $\diamondsuit$\), and $\(\clubsuit$\)), such that there is exactly one card for any given rank and suit. Two of the suits (\($\spadesuit$ and $\clubsuit$)\) are black and the other two suits (\($\heartsuit$ and $\diamondsuit$\)) are red. The deck is randomly arranged. What is the probability that the top card is a face card (a Jack, Queen, or King)?

 

 

look closely at the problem

off-topic
 Apr 1, 2020
 #1
avatar+336 
+1

out of 13 cards, 3 will match your cases. So, the total is 13, and the acceptable cases are 3, so the answer is 3/13.

 Apr 1, 2020
 #3
avatar+38 
0

so 4 suits and 3 J Q and K's per suit right 

4*3=12 so

12 out of the 52 cards are the ones we want

12/52 =3/13 =.023

and that's as a percent is around 2.3%

UwU

 hope this helps

 Apr 1, 2020

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