can you help me with this question thank you so much

Guest Sep 6, 2017

edited by
Guest
Sep 6, 2017

#1**+2 **

Let's calculate the area. The area of a rectangle is equal to the length of the length multiplied by the length of the height.

\(5\frac{1}{6}*2\frac{2}{7}\) | Convert both fractions to an improper fraction. |

\(\frac{6*5+1}{6}*\frac{7*2+2}{7}\) | Let's simplify this. |

\(\frac{31}{6}*\frac{16}{7}\) | 16 and 6 have a GCF of 2, which can be factored out to ease computation. |

\(\frac{31}{3}*\frac{8}{7}\) | Now, multiply the numerator and denominator together. |

\(\frac{248}{21}\) | Now, we must convert it back to a mixed number as the question asks to represent the area as a mixed number. Without going over, 21 goes into 248 11 times. |

\(11+\frac{248-21*11}{21}\) | |

\(11+\frac{248-231}{21}\) | |

\(11\frac{17}{21}\) | |

TheXSquaredFactor Sep 7, 2017

#1**+2 **

Best Answer

Let's calculate the area. The area of a rectangle is equal to the length of the length multiplied by the length of the height.

\(5\frac{1}{6}*2\frac{2}{7}\) | Convert both fractions to an improper fraction. |

\(\frac{6*5+1}{6}*\frac{7*2+2}{7}\) | Let's simplify this. |

\(\frac{31}{6}*\frac{16}{7}\) | 16 and 6 have a GCF of 2, which can be factored out to ease computation. |

\(\frac{31}{3}*\frac{8}{7}\) | Now, multiply the numerator and denominator together. |

\(\frac{248}{21}\) | Now, we must convert it back to a mixed number as the question asks to represent the area as a mixed number. Without going over, 21 goes into 248 11 times. |

\(11+\frac{248-21*11}{21}\) | |

\(11+\frac{248-231}{21}\) | |

\(11\frac{17}{21}\) | |

TheXSquaredFactor Sep 7, 2017