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can you help me with this question thank you so much

Guest Sep 6, 2017
edited by Guest  Sep 6, 2017

Best Answer 

 #1
avatar+1088 
+2

Let's calculate the area. The area of a rectangle is equal to the length of the length multiplied by the length of the height. 

 

\(5\frac{1}{6}*2\frac{2}{7}\) Convert both fractions to an improper fraction.
\(\frac{6*5+1}{6}*\frac{7*2+2}{7}\) Let's simplify this.
\(\frac{31}{6}*\frac{16}{7}\) 16 and 6 have a GCF of 2, which can be factored out to ease computation.
\(\frac{31}{3}*\frac{8}{7}\) Now, multiply the numerator and denominator together.
\(\frac{248}{21}\) Now, we must convert it back to a mixed number as the question asks to represent the area as a mixed number. Without going over, 21 goes into 248 11 times.
\(11+\frac{248-21*11}{21}\)  
\(11+\frac{248-231}{21}\)  
\(11\frac{17}{21}\)  
   
   
TheXSquaredFactor  Sep 7, 2017
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1+0 Answers

 #1
avatar+1088 
+2
Best Answer

Let's calculate the area. The area of a rectangle is equal to the length of the length multiplied by the length of the height. 

 

\(5\frac{1}{6}*2\frac{2}{7}\) Convert both fractions to an improper fraction.
\(\frac{6*5+1}{6}*\frac{7*2+2}{7}\) Let's simplify this.
\(\frac{31}{6}*\frac{16}{7}\) 16 and 6 have a GCF of 2, which can be factored out to ease computation.
\(\frac{31}{3}*\frac{8}{7}\) Now, multiply the numerator and denominator together.
\(\frac{248}{21}\) Now, we must convert it back to a mixed number as the question asks to represent the area as a mixed number. Without going over, 21 goes into 248 11 times.
\(11+\frac{248-21*11}{21}\)  
\(11+\frac{248-231}{21}\)  
\(11\frac{17}{21}\)  
   
   
TheXSquaredFactor  Sep 7, 2017

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