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# can someone please help me with this question im stuck

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can you help me with this question thank you so much

Guest Sep 6, 2017
edited by Guest  Sep 6, 2017

#1
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Let's calculate the area. The area of a rectangle is equal to the length of the length multiplied by the length of the height.

 $$5\frac{1}{6}*2\frac{2}{7}$$ Convert both fractions to an improper fraction. $$\frac{6*5+1}{6}*\frac{7*2+2}{7}$$ Let's simplify this. $$\frac{31}{6}*\frac{16}{7}$$ 16 and 6 have a GCF of 2, which can be factored out to ease computation. $$\frac{31}{3}*\frac{8}{7}$$ Now, multiply the numerator and denominator together. $$\frac{248}{21}$$ Now, we must convert it back to a mixed number as the question asks to represent the area as a mixed number. Without going over, 21 goes into 248 11 times. $$11+\frac{248-21*11}{21}$$ $$11+\frac{248-231}{21}$$ $$11\frac{17}{21}$$
TheXSquaredFactor  Sep 7, 2017
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#1
+1845
+2
 $$5\frac{1}{6}*2\frac{2}{7}$$ Convert both fractions to an improper fraction. $$\frac{6*5+1}{6}*\frac{7*2+2}{7}$$ Let's simplify this. $$\frac{31}{6}*\frac{16}{7}$$ 16 and 6 have a GCF of 2, which can be factored out to ease computation. $$\frac{31}{3}*\frac{8}{7}$$ Now, multiply the numerator and denominator together. $$\frac{248}{21}$$ Now, we must convert it back to a mixed number as the question asks to represent the area as a mixed number. Without going over, 21 goes into 248 11 times. $$11+\frac{248-21*11}{21}$$ $$11+\frac{248-231}{21}$$ $$11\frac{17}{21}$$