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The sum of 4 consecutive even integers is less than 192. What are the largest 4 integers that would work?

 Apr 12, 2018
 #1
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Let  x  be the first integer

x + 2  the second

x + 4 the third

x + 6  the fourth

 

So  we have

 

x  + (x + 2)  + ( x + 4) + ( x + 6)  < 192  simplify

 

4x + 12 <   192     subtract  12  from  both sides

 

4x < 180     divide both sides by  4

 

x < 45

 

So......the greatest even integer < 45  is 44

 

So...the four consecutive even integers   are  44  46   48   and 50

 

And their sum is 188

 

 

cool cool cool

 Apr 12, 2018

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