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The length of a rectangle is $3x+10$ feet and its width is $x+12$ feet. If the perimeter of the rectangle is 76 feet, how many square feet are in the area of the rectangle?

 Mar 27, 2020
edited by helpppp  Mar 27, 2020
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Perimeter  =        2 ( W + L)

 

So....this MUST  mean that

 

76  = 2  [ (x + 12)  + (3x + 10) ]    divide both sides  by  2  and simplify the stuff in the  brackets

 

38  =  4x + 22       subtract  22 from each side

 

16 =  4x    divide  both  sides  by  4

 

4 =  x  

 

To find the area  =  L * W

 

So....subbing in   4   we  have that

 

(4 + 12)  ( 3 (4)  + 10) 

 

(16)  ( 12 + 10)

 

(16) ( 22)  =

 

352  ft^2 

 

 

cool cool cool

 Mar 27, 2020

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