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 Apr 30, 2020
 #1
avatar+111438 
+1

First one

 

y  = 5x

 

Let x = 2a

 

y = 5(2a)  = 10a

 

When x doubles  we  have

 

y = 5(4a)  =  20a

 

So....when x  doubles  y  doubles    ⇒  "A"

 

Second one

 

y   =5/x

 

Let x = 2a

 

y = 5 / (2a)  =  (1/2)*5a

 

Now....let  x triple and we have that

 

y = 5 / (6a)  =    (1/6) * 5a

 

So....when x triples, y  is 1/3 of its original value  ⇒  "D"

 

 

 

cool cool cool

 Apr 30, 2020
 #2
avatar+111438 
+1

x : y  =   3 : 1

 

x / y  =  3 / 1     and we can write

 

y / x  =  1 /3

 

y  =(1/3) x

 

 

 

cool cool cool

 Apr 30, 2020

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