+0  
 
+1
179
1
avatar+545 

https://vle.mathswatch.co.uk/images/questions/question15619.png

 

 

winkwinkwink

lynx7  Feb 13, 2018

Best Answer 

 #1
avatar+7324 
+3

 

Since they form a straight line....

 

(x + 25)° + (2x + 50)°   =   180°      Now we can find the value of  x .

                                                       Simplify the left side of the equation.

x + 25 + 2x + 50   =   180

 

3x + 75   =   180

                                                       Subtract  75  from both sides of the equation.

3x   =   105

                                                       Divide both sides by  3 .

x   =   35

 

In order for  AC  to be parallel to  EF,   2x + 50   must be equal to  5x - 55 .

 

2x + 50   \(\stackrel{?}{=}\)   5x - 55

                                               We know that  x = 35 , so plug in  35  for  x .

2(35) + 50   \(\stackrel{?}{=}\)   5(35) - 55

 

70 + 50   \(\stackrel{?}{=}\)   175 - 55

 

120   \(\stackrel{?}{=}\)   120       Yes, so  AC  is parallel to  EF .

hectictar  Feb 13, 2018
 #1
avatar+7324 
+3
Best Answer

 

Since they form a straight line....

 

(x + 25)° + (2x + 50)°   =   180°      Now we can find the value of  x .

                                                       Simplify the left side of the equation.

x + 25 + 2x + 50   =   180

 

3x + 75   =   180

                                                       Subtract  75  from both sides of the equation.

3x   =   105

                                                       Divide both sides by  3 .

x   =   35

 

In order for  AC  to be parallel to  EF,   2x + 50   must be equal to  5x - 55 .

 

2x + 50   \(\stackrel{?}{=}\)   5x - 55

                                               We know that  x = 35 , so plug in  35  for  x .

2(35) + 50   \(\stackrel{?}{=}\)   5(35) - 55

 

70 + 50   \(\stackrel{?}{=}\)   175 - 55

 

120   \(\stackrel{?}{=}\)   120       Yes, so  AC  is parallel to  EF .

hectictar  Feb 13, 2018

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