In a particular game, a spinner with four equally-sized sectors labeled 1, 4, 6, and 8 is spun twice. One turn is considered 2 spins of the spinner.
If the sum of the spins is even, you move forward 6 spaces. Otherwise, you move back 2 spaces.
What is the mathematical expectation for the number of spaces moved in one turn?
3 spaces forward
1 space backward
3 spaces backward
1 space forward
i believe the answer is 0 for all of them, since the only amount of spaces that you can move is even, and an even number + even number = even number and even number - even number = even number
edit: aaaaaah. misunderstood the problem. CPhill got it right!